Topicmb4608f669774696d_1528449000663_0Topic

Properties of similarity

Levelmb4608f669774696d_1528449084556_0Level

Third

Core curriculummb4608f669774696d_1528449076687_0Core curriculum

VIII. Plane geometry. The student:

9) uses relations between perimeters and areas of similar figuressimilar figuressimilar figures.

Timingmb4608f669774696d_1528449068082_0Timing

45 minutes

General objectivemb4608f669774696d_1528449523725_0General objective

Reasoning, including multiple‑stage arguments, giving arguments, justifying the correctness of reasoning, distinguishing a proof from an example.

Specific objectivesmb4608f669774696d_1528449552113_0Specific objectives

1. Using relations between perimeters and areas of similar figuressimilar figuressimilar figures.

2. Communicating in English, developing basic mathematical, computer and scientific competences, developing learning skills.

Learning outcomesmb4608f669774696d_1528450430307_0Learning outcomes

The student:

- aapplies relations between perimeters and areas of similar figuressimilar figuressimilar figures to solve problems,

- carries out geometric proofs using relations between perimeters and areas of similar figures.

Methodsmb4608f669774696d_1528449534267_0Methods

1. Discussion.

2. Situational analysis.

Forms of workmb4608f669774696d_1528449514617_0Forms of work

1. Individual work.

2. Group work.

Lesson stages

Introductionmb4608f669774696d_1528450127855_0Introduction

The teacher informs students that in the lesson they will learn the relations between the perimeters and areas of similar figuressimilar figuressimilar figures and they will use them to solve geometric problems.

Discussion
Students work in groups and collect arguments to show that in k‑like triangles:

- the height of one triangle is proportional to the corresponding heights of the second triangle in the ratio k (group 1),
- the medians of one triangle are proportional to the corresponding medians of the second triangle on the same ratio k (group 2),
- sections of bisectors of one triangle are proportional to the bisector sections of the second triangle in the same ratio k (group 3).

The conclusion of the discussion may be the following:

- The particular sections of one triangle (heights, medians, bisector sections, etc.) are proportional to the corresponding segments of the second triangle in the same ratio k.mb4608f669774696d_1527752256679_0- The particular sections of one triangle (heights, medians, bisector sections, etc.) are proportional to the corresponding segments of the second triangle in the same ratio k.

Proceduremb4608f669774696d_1528446435040_0Procedure

Task
The triangle ABC with sides a, b, c is given and the triangle A'B'C' is similar to it on the ratio k.
Designate:

1. The ratio of the perimeterperimeterperimeter of triangle A'B'C' to the perimeterperimeterperimeter of the triangle ABC.
2. The ratio of the areaareaarea of triangle A'B'C' to the areaareaarea of triangle ABC.

Students work in pairs, proving:

1. The relation between the perimeters of two similar triangles.
2. The relation between the areas of similar triangles.

Selected pairs present the results that are discussed.

Discussion
Can the proved relations for perimeters and areas of similar triangles be applicable to any similar figure? How?

Students work in pairs, using computers, analyze the relations between the areas of similar figuressimilar figuressimilar figures.

Task
Open the Geogebry applet: „The scale of similarity and the areas of figures”. Analyze the relations between squares, similar triangles, similar polygons, and circles. Formulate the conclusion in the form of a theorem.

[Geogebra applet]

Theorem – Perimeters and area of similar figures.
- If figure F' is similar to figure F on the ratio k, then the ratio of their perimeters is equal to k, and the ratio of areas is equal to kIndeks górny 2.
mb4608f669774696d_1527752263647_0Theorem – Perimeters and area of similar figures.
- If figure F' is similar to figure F on the ratio k, then the ratio of their perimeters is equal to k, and the ratio of areas is equal to kIndeks górny 2.

Students individually perform the task, then present solutions and explain doubts.

Task
In the triangle ABC, a straight line parallel to the base has been led so that the areaareaarea of the cut triangle is 8 times larger than the rest of the triangle ABC. The perimeters of ABC triangle is 27. Calculate the perimeterperimeterperimeter of the cut triangle.

Task
In the ABCD trapezium, the AC and BD diagonals intersect at the point S. The areaareaarea of ASB triangleis 9, and the area of CSD triangle  is equal to 4. Calculate the areaareaarea of the trapezium.

Task
In rhombusrhombusrhombus ABCD diagonals have lengths of 12 cm and 6 cm, respectively. The area of ABCD rhombusrhombusrhombus similar to A'B'C'D' is equal to 72 cmIndeks górny 2. Find diagonal lengths in A'B'C'D' rhombus.

An extra task:
The diagonals of the trapezium divide it into four triangles. Prove that the areaareaarea of the trapezium is equal (S1+S2)2 where S1 and S2 are the triangles  containing the trapezium bases.

Lesson summarymb4608f669774696d_1528450119332_0Lesson summary

Students do the revision exercises.

Then together summarize the class, by formulating the conclusions to memorize.

- If figure F' is similar to figure F on the ratio k, then the ratio of the perimeterperimeterperimeter of figure F' to the perimeterperimeterperimeter of figure F is k, and the ratio of their areas is equal to kIndeks górny 2.

Selected words and expressions used in the lesson plan

areaareaarea

perimeterperimeterperimeter

ratio of arearatio of arearatio of area

rhombusrhombusrhombus

similar figuressimilar figuressimilar figures

similarity ratiosimilarity ratiosimilarity ratio

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similar figures1
similar figures

figury podobne

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obwód

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area1
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pole

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rhombus1
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romb

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stosunek pól

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skala podobieństwa

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wymowa w języku angielskim: similarity ratio